Why isn’t the & symbol used in printf?

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Why isn’t the & symbol used in printf?

Therefore, square_it cannot let the caller see the change.Now, although printf doesn’t need change its argument (it is an output function) scanf scanf scanf The format string (scan formatted) is Control parameters for various functions to specify the layout of the input string. These functions can then divide the string and convert to a value of the appropriate data type. String scanning functions are usually provided in the standard library. https://en.wikipedia.org › Wiki › Scanf_format_string

scanf format string – Wikipedia

Indeed (it is an input function). So it takes a variable pointer (address) as a parameter.

Can we use & in printf?

in printf…it works. why is that? There are also differences between format specifiers, such as when using %c or %d in scanf, the & (ampere) symbol does not need to be placed in printf.

Why is the ampersand not used in strings in C?

If it is a string (array of characters), The variable itself points to the first element of the array has a problem. Therefore, there is no need to use the « & » operator to pass the address. ‘&’ is used to get the address of a variable.

Why use ampersand in scanf?

Ampersand (&) allows us to pass the address of the variable number, this is the memory location where we store the information read by scanf. . . The « %s » in scanf allows the function to recognize the user input as a string data type, which matches the data type of our variable word.

What happens if I don’t use & in scanf?

The program will compile successfully. It prints numbers incorrectly, but it runs to the end without crashing.

The Secret of printf(): C Programming

https://www.youtube.com/watch?v=Y9kUWsyyChk

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