0 A mixture of two enantiomers.

Is it an example of an inner orbital complex?

Let us consider an example to understand the formation of inner orbital complexes.the electron configuration of Cobalt (Co) is [Ar]3d74s2. Since the NH3 ligand is uncharged, the oxidation state of the Co atom should be +3. The electron configuration of Co+3 is [Ar]3d6.

Which of the following is an example of an inner orbital complex?

i) Inner orbital complexes using inner d-orbitals in hybridization; e.g. [Co(NH3)]3+ is the inner orbital because the complex uses the inner d orbital, so its hybridization is d2sp3. Also known as low spin complexes.

What type of hybridization does the inner-orbital and outer-orbital complexes exhibit?

The key difference between inner orbital complexes and outer orbital complexes is that the hybridization of the atomic orbitals of the central metal atom of the inner orbital complexes involves inner shell d track Whereas the hybridization of the atomic orbitals of the central metal atom of the outer orbital complex involves the outermost shell d…

How many complexes show optical isomerism?

Complexes showing optical isomerism exist in two formsright-handed and left-handed forms.

What is optical isomerism?

Optical isomers are two compounds containing the same number and kind of atoms, and bonds (i.e. the same connectivity between atoms), and different spatial arrangements of atoms, but they have mirror images that are not superimposable. Each non-superimposable mirror-image structure is called an enantiomer.

Does Mabcd show optical isomerism?

In the Mabcd tetrahedral complex, No optical isomerism can be observed.

Which of the following can show optical isomerism?

5) Structurally 2-Bromobutane There is one chiral carbon atom, indicated by an asterisk in the structure. The carbon atom is attached to four different atoms and the group attached to it, so it is a chiral carbon and it will show optical isomerism.

Which of the following can show geometric isomerism and optical isomerism?

Therefore, we conclude that the only compounds that show both geometric and optical isomerism are [Co(en)2Cl2]+. So, the correct answer is « Option A ».

Is ma2b4 optically active?

No, they only exhibit geometric (cis-trans) isomerism. This type of complex has an octahedral geometry.The cis isomer has two planes of symmetry, so it is Optically inert. The trans isomer has five such planes, so it is also optically inert.